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Given the temperature, how does one calculate the proportion of energy radiated by a black body as visible light or any arbitrary range of frequencies? - Quora
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SOLVED: BLACK-BODY RADIATION The energy density (energy per unit volume per unit frequency range) of radiation inside a cavity is given by: E(w) = T^2c^3/(e^(nwT) - 1), where h is Planck's constant,
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SOLVED: Blackbody Radiation: A supernova remnant has an angular diameter θ = 30 arcseconds and a flux at 800 MHz of F = 1.9 x 10^-19 erg cm^-3 s^-1 Hz^-1. Assume that
Spectral Calculator-Hi-resolution gas spectra
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